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mysql 综合练习(一)

辉猪子 • 3 年前 • 218 次点击  
-- 创建部门表
DROP TABLE IF EXISTS dept; 
CREATE TABLE dept(
    -- 部门编号
    deptno int PRIMARY KEY, 
    -- 部门名称
    dname VARCHAR(14), 
    -- 部门所在地
    loc VARCHAR(13)
  );

-- 向部门表插入数据
INSERT INTO dept VALUES (10,'ACCOUNTING','NEW YORK');
INSERT INTO dept VALUES (20,'RESEARCH','DALLAS');
INSERT INTO dept VALUES (30,'SALES','CHICAGO');
INSERT INTO dept VALUES (40,'OPERATIONS','BOSTON');

-- 创建员工表
DROP TABLE IF EXISTS emp;
CREATE TABLE emp(
  -- 员工编号
  empno int PRIMARY KEY, 
  -- 员工姓名
  ename VARCHAR(10), 
  -- 工作岗位
  job VARCHAR(9), 
  -- 直属领导
  mgr int, 
  -- 入职时间
  hiredate DATE, 
  -- 工资
  sal double, 
  -- 奖金
  comm double, 
  -- 所属部门
  deptno int
);


-- 为员工表表添加外键约束
ALTER TABLE emp ADD CONSTRAINT FOREIGN KEY EMP(deptno) REFERENCES dept (deptno);

-- 向员工表插入数据
INSERT INTO emp VALUES(7369,'SMITH','CLERK',7902,"1980-12-17",800,NULL,20);
INSERT INTO emp VALUES(7499,'ALLEN','SALESMAN',7698,'1981-02-20',1600,300,30);
INSERT INTO emp VALUES(7521,'WARD','SALESMAN',7698,'1981-02-22',1250,500,30);
INSERT INTO emp VALUES(7566,'JONES','MANAGER',7839,'1981-04-02',2975,NULL,20);
INSERT INTO emp VALUES(7654,'MARTIN','SALESMAN',7698,'1981-09-28',1250,1400,30);
INSERT INTO emp VALUES(7698,'BLAKE','MANAGER',7839,'1981-05-01',2850,NULL,30);
INSERT INTO emp VALUES(7782,'CLARK','MANAGER',7839,'1981-06-09',2450,NULL,10);
INSERT INTO emp VALUES(7788,'SCOTT','ANALYST',7566,'1987-07-03',3000,NULL,20);
INSERT INTO emp VALUES(7839,'KING','PRESIDENT',NULL,'1981-11-17',5000,NULL,10);
INSERT INTO emp VALUES(7844,'TURNER','SALESMAN',7698,'1981-09-08',1500,0,30);
INSERT INTO emp VALUES(7876,'ADAMS','CLERK',7788,'1987-07-13',1100,NULL,20);
INSERT INTO emp VALUES(7900,'JAMES','CLERK',7698,'1981-12-03',950,NULL,30);
INSERT INTO emp VALUES(7902,'FORD','ANALYST',7566,'1981-12-03',3000,NULL,20);
INSERT INTO emp VALUES(7934,'MILLER','CLERK',7782,'1981-01-23',1300,NULL,10);


-- 创建工资等级表
DROP TABLE IF EXISTS salgrade;
CREATE TABLE salgrade(
  -- 等级
  grade int, 
  -- 最低工资
  losal double, 
  -- 最高工资
  hisal double
);

-- 向工资等级表插入数据
INSERT INTO salgrade VALUES (1,700,1200);
INSERT INTO salgrade VALUES (2,1201,1400);
INSERT INTO salgrade VALUES (3,1401,2000);
INSERT INTO salgrade VALUES (4,2001,3000);
INSERT INTO salgrade VALUES (5,3001,9999);
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– 01、查询部门编号为30的部门的员工详细信息

SELECT * FROM emp WHERE deptno = 30;

– 02、查询从事clerk工作的员工的编号、姓名以及其部门号

SELECT empno,ename,deptno FROM emp WHERE job = ‘clerk’;

– 03、查询奖金多于基本工资的员工的信息

SELECT * FROM emp WHERE comm > sal;

– 04、查询奖金多于基本工资60%的员工的信息

SELECT * FROM emp WHERE comm > sal * 0.6;

– 05、查询部门编号为10的部门经理和部门编号为20的部门中工作为CLERK的职员信息

SELECT * FROM emp WHERE deptno = 10 AND job=‘MANAGER’ OR deptno = 20
AND job = ‘CLERK’;

– 06、查询部门编号为10的部门经理或部门编号为20的部门工作为CLERK的职员信息或者既不是经理也不是CLERK但是工资高于2000的员工信息

SELECT * FROM emp WHERE deptno = 10 AND job=‘MANAGER’ OR deptno = 20
AND job = ‘CLERK’ OR job NOT IN (‘MANAGER’,‘CLERK’) AND sal > 2000 ;

– 07、查询获得奖金的员工的信息

SELECT * FROM emp WHERE comm > 0 and comm is not null;

– 08、查询奖金少于100或者没有获得奖金的员工的信息

SELECT * FROM emp WHERE comm < 100 OR comm IS NULL;

– 09、查询姓名以A、B、S开头的员工的信息

SELECT * FROM emp WHERE ename LIKE ‘A%’ OR ename LIKE ‘B%’ OR ename
LIKE ‘S%’;

– 10、查询找到姓名长度为6个字符的员工的信息

SELECT * FROM emp WHERE LENGTH(ename) = 6;

//几个下划线就占几个字符
SELECT * FROM emp WHERE ename LIKE ‘______’;

– 11、查询姓名中不包含R字符的员工信息。

SELECT * FROM emp WHERE ename NOT LIKE ‘%R%’;

– 12、查询员工的详细信息并按姓名排序

SELECT * FROM emp ORDER BY ename ASC;

– 13、查询员工的信息并按工作降序工资升序排列

SELECT * FROM emp ORDER BY job DESC , sal ASC;

– 14、计算员工的日薪(按30天计)
//As 取别名,可要可不要

SELECT ename,sal/30 AS '日薪' FROM emp;

– 15、查询姓名中包含字符A的员工的信息

SELECT * FROM emp WHERE ename LIKE ‘’%A%’;

– 16、查询拥有员工的部门的部门名和部门号

SELECT DISTINCT d.dname, d.deptno FROM dept d,emp e WHERE d.deptno =
e.deptno;

Select DISTINCT d.deptno,d.dname from emp e, dept d where e.JOB IS NOT
NULL;

– 17、查询工资多于smith的员工信息。

SELECT *FROM emp WHERE sal > (SELECT sal FROM emp WHERE ename =
‘smith’);

………………**` 后面的还没怎么弄懂,会持更新的,感谢关注 在这里插入图片描述

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