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基于堆的优先队列和堆排序-python实现

美雨知春 • 3 年前 • 233 次点击  

采用树形结构实现优先队列的技术称为堆
优先队列,就是值最小的排在队头,值最大的排在队尾,还有插入新元素的问题,插入的算法复杂度O(n),如果采用基于堆的优先队列,算法复杂度O(lgn),插入堆采用插入元素向上筛选,就是从底部到顶部一级一级跳跃,直到上一个root比元素值小或者本身到了root,删除元素向下筛选

class PrioQueue():
    def __init__(self,elist=[]):
        self._elems = list(elist)
        if elist:
            self.buildheap()
    def is_empty(self):
        return not self._elems
    def peek(self):
        if self.is_empty():
            raise PrioQueueError("in peek")
        return self._elems[0]
    def enqueue(self,e):
        self._elems.append(None) #add a dummy element
        self.siftup(e,len(self._elems) -1 )
    def seftup(self , e, last):
        elems,i,j=self._elems,last,(last-1)//2
        while i>0 and e < elems[j]:
            elems[i] = elems[j]
            i,d=j,(j-1)//2
        elems[i] = e
    def dequeue(self):
        if self.is_empty():
            raise PrioQueueError("in dequeue")
        elems = self._elems
        e0 = elems[0]
        e = elems.pop()
        if len(elems) > 0:
            self.siftdowm(e,0,len(elems))
        return e0
    def siftdown(self, e, begin, end):
        elems,i,j = self._elems, begin, begin*2+1
        while j< end :
            if j+1 < end and elems[j+1] < elems[j]:
                j +=1
            if e < elems[j]:
                break
                elems[i] = elems[j]
                i,j = j, 2*j+1
            elems[i] = e
    def buildheap(self):
        end = len(self._elems)
        for i in range(end/2,-1,-1):
            self.siftdown(self._elems[i],i,end)
    def printnum(self):
        print self._elems

堆排序:如果一个连续表里存储的数据是一个小顶堆,按优先队列的方式反复弹出堆顶元素,能够得到一个递增序列。基于这个技术可以完成堆排序,下面是堆排序算法,siftdown是向下弹出堆顶元素,siftup是向上插入

def heap_sort(elems):
    def siftdown(elems, e, begin, end):
        i,j = begin, begin*2+1
        while j< end:
            if j+1 < end and elems[j+1] <elems[j]:
                j +=1
            if e<elems[j]:
                break
            elems[i] = elems[j]
            i,j = j, 2*j+1
        elems[i] = e
        end = len(elems)
        for i in range(end//2, -1, -1):
            siftdown(elems, elems[i],i, end)
        for i in range((end -1),0,-1):
            e = elems[i]
            elems[i] = elems[0]
            siftdown(elems,e,0,i)
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