我想对给定路径中可用的所有文件(库)执行相同的函数(给出输出A、B、C、D)。我正在尝试将输出(A、B、C、D)写入xlsx中工作表的四个不同列中。此外,xlsx的图纸名称应与路径中可用的受尊重文件相同。
我编写了以下代码:
def create_xlsx_file(xlsx_name, file_path):
workbook = xlsxwriter.Workbook(xlsx_name) ### creates a xlsx file
workbook.close()
libraries=os.listdir(file_path)
file_path=os.chdir(file_path)
for library in libraries: ### to create the sheets named same as the library
# print(library)
if library.endswith('.txt'):
# library=file_path+library
# print(library)
main(library, xlsx_name)
def main(library, xlsx_name): ###library = all files in the given path
directory=os.chdir(os.getcwd())
workbook = openpyxl.load_workbook(xlsx_name)
worksheet = workbook.create_sheet(library, 0)##### creates workshhets named same as library name
#print('library is: - ',library)
sheet=workbook[library] ###to create column headers
sheet.cell(column=1, row=1, value='value_A')
sheet.cell(column=2, row=1, value='value_B')
sheet.cell(column=3, row=1, value='value_C')
sheet.cell(column=4, row=1, value='value_D')
workbook.save(xlsx_name)
with open(library, 'r') as library:
for line in library:
A=line.split(' ')[0]
B=line.split(' ')[1]
C=line.split(' ')[2]
D=line.split(' ')[3]
sheet=workbook[library]
sheet.cell(column=1, row=sheet.max_row+1, value=str(A))
sheet.cell(column=2, row=sheet.max_row, value=str(B))
sheet.cell(column=3, row=sheet.max_row, value=str(C))
sheet.cell(column=4, row=sheet.max_row, value=str(D))
print(f'library {library} has been written at {os.getcwd()}')
#time.sleep(1)
workbook.save(xlsx_name)
这段代码对我来说非常好,但写xlsx文件太慢了,因为我的路径有数百个。txt库和每个库都有数百万行。
我可以将输出(A、B、C、D)保存为。txt格式,然后可以手动编写xlsx文件,但这是非常费力的。
有没有办法加快这一进程?或提供其他任何快速xlsx写入程序?
任何帮助都将不胜感激。
谢谢
