当字符串是模式时,python替换单词而不是单词的一部分

我能想到的最简单的方法是将re.sub与backreference groups结合使用。您可以使用以下方法来完成您的任务。

re.sub(r'([_|\s])(?:you)(_)', r"\1we\2", s)

在这里,它是第一组 ([_|\s]) 第二组是 (_) . (?:you) 是非捕获组。在替换字符串中\1和\2指上述组。所以最终你的替换字符串变成 <whatever character before you>we<whatever character after you>

既然你知道你想要什么,就用你不想要的作为边界条件。

(?<![^\W_])you(?![^\W_])

https://regex101.com/r/z2TDXA/1

.replace()

s = "_you_don't_ think_you_don't_* you_don't__ you_don't_know_your_youth"
string.replace('_you_', '_we_').replace(' you_', ' we_')

产量

“我们不认为我们不知道你的年轻人”

[a-zA-Z] - Matches anything that is a single character

![a-zA-Z] - Anything that is not a single English character

? - One or zero match of pattern

(?<![a-zA-Z])you(?![a-zA-Z]) - This matches "you" if not preceded and 
not followed by a letter

import re
s = "*_you_don't_* think_you_don't_* you_don't_*_* you_don't_know_your_youth"
print re.sub(r'(?<![a-zA-Z])you(?![a-z-Z])', 'we', s)

*_we_don't_* think_we_don't_* we_don't_*_* we_don't_know_your_youth

Demo

(?<=\b|_)you(?=\b|_)

Demo