python中的replace函数给出了错误的结果

Artur • 4 年前 • 662 次点击

干膜厚度:

    Sample  AlmostFinal  
    1          KOPLA234        
    1          KOPLA234
    2          RWPLB253
    3          MMPLA415
    3          MMPLA415

KOPL 和 RWP MM 到Kolpol,最后一个字符a/b应保留。所以结果应该是:

    Sample  AlmostFinal  Final
    1          KOPLA234  KOLPOLA234      
    1          KOPLA234  KOLPOLA234
    2          RWPLB253  KOLPOLB253
    3          MMPLA415  KOLPOLA415
    3          MMPLA415  KOLPOLA415

    dfF['Final'] = (dfF['AlmostFinal'].replace({'KOPL':'KOLPOL'}, regex = True))
    dfF['Final'] = (dfF['AlmostFinal'].replace({'RWP':'KOLPOL'}, regex = True))
    dfF['Final'] = (dfF['AlmostFinal'].replace({'MMPL':'KOLPOL'}, regex = True))

并且:如果我评论第2行和第3行代替了Kopl的工作。

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662 次点击

文章 [ 3 ] | 最新文章 4 年前

• 1 楼

DYZ 4 年前

dfF['Final'] = dfF['AlmostFinal']\
               .replace({'KOP|RWP|MMP': 'KOLPO'}, regex = True)

• 2 楼

Masklinn 4 年前

{
    'KOPL':'KOLPOL',
    'RWP':'KOLPOL',
    'MMP':'KOLPOL',
}

df['Final']

• 3 楼

cs95 4 年前

replace regex=True

df['Final'] = df['AlmostFinal'].replace(
    [r'KOPL', r'RWP.*?(?=A|B)', r'MM.*(?=A|B)'], 'KOLPOL', regex=True)
df

   Sample AlmostFinal       Final
0       1    KOPLA234  KOLPOLA234
1       1    KOPLA234  KOLPOLA234
2       2    RWPLB253  KOLPOLB253
3       3    MMPLA415  KOLPOLA415
4       3    MMPLA415  KOLPOLA415

pat = ['KOPL', 'RWP', 'MM']
df['Final'] = df['AlmostFinal'].replace(
    [rf'{p}.*(?=A|B)' for p in pat], 'KOLPOL', regex=True)  # need python3.6+
df

   Sample AlmostFinal       Final
0       1    KOPLA234  KOLPOLA234
1       1    KOPLA234  KOLPOLA234
2       2    RWPLB253  KOLPOLB253
3       3    MMPLA415  KOLPOLA415
4       3    MMPLA415  KOLPOLA415

pat = ['KOPL', 'RWPL', 'MMPL']
df['AlmostFinal'].replace(pat, 'KOLPOL', regex=True)

0    KOLPOLA234
1    KOLPOLA234
2    KOLPOLB253
3    KOLPOLA415
4    KOLPOLA415
Name: AlmostFinal, dtype: object

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