如何制作 stream_socket_get_name 从远程客户端返回真实的IP地址?

$ip = stream_socket_get_name($socket, true);

上面的返回类似于 127.0.0.1:39872

小精灵

server {
    listen 8443 ssl;
    server_name  websocket.example.com;

    ssl_certificate  /var/ini/ssl/public.crt;
    ssl_certificate_key  /var/ini/ssl/private.key;

    location / {
        proxy_redirect  off;

        proxy_pass  http://127.0.0.1:9000/;
        proxy_http_version  1.1;
        proxy_set_header  Upgrade $http_upgrade;
        proxy_set_header  Connection "upgrade";
        proxy_read_timeout  300;

        proxy_set_header  X-Real-IP $remote_addr;
        proxy_set_header  X-Forwarded-Proto https;
        proxy_set_header  X-Forwarded-For $remote_addr;
        proxy_set_header  X-Forwarded-Host $remote_addr;
    }
}