python:如何将csv数据转换为数组

import csv

output = []

with open('test1.csv', 'r') as f:
    content = csv.reader(f, delimiter=',')

    for line in content:
        clean_line = filter(None, line)  # remove extra spaces
        output.append([[int(i)] for i in clean_line])

>>> print output
[[[11], [10], [8], [12], [13], [11]], [[0], [1], [0], [2], [3], [0]], [[5], [15], [13], [11], [18], [18]]]  

测试结果与预期输出相符:

desired = [ [[11],[10],[8],[12],[13],[11]], 
            [[0],[1],[0],[2],[3],[0]], 
            [[5],[15],[13],[11],[18],[18]] ]

# print output == desired   # True

1. 首先,您可以将文件读取到数组中。
2. 之后,可以使用map函数将每个字符串列表转换为整数列表

解决方案:

import csv
with open('input.csv', 'rb') as f:
    reader = csv.reader(f)
    lines = [row for row in reader]

array = [map(int,l) for l in lines]

array
[[11, 10, 8, 12, 13, 11], [0, 1, 0, 2, 3, 0], [5, 15, 13, 11, 18, 18]]

读取文件并从中获取项目列表:

import csv

results = []

with open('some_array.csv','r') as f:
    lines = csv.reader(f)
    for line in lines:
        results.append([[int(i)] for i in line])

>>results
[[['11'], ['10'], ['8'], ['12'], ['13'], ['11']],
 [['0'], ['1'], ['0'], ['2'], ['3'], ['0']],
 [['5'], ['15'], ['13'], ['11'], ['18'], ['18']]]