mysql 5.5-用上面的值填补空白

我有一个表,其中包含不同报告日期的全球销售数据,如下所示:

+------------+------+------------+---------+
| Closed     | Open | Plan       | Station |
+------------+------+------------+---------+
| 2018-10-23 | NULL | NULL       | A       |
| 2018-10-22 | NULL | NULL       | NULL    |
| 2018-10-22 | NULL | NULL       | B       |
| 2018-10-22 | NULL | NULL       | NULL    |
| NULL       | NULL | 2018-10-23 | C       |
| NULL       | NULL | 2018-10-22 | NULL    |
| NULL       | NULL | 2018-10-22 | NULL    |
+------------+------+------------+---------+

CREATE TABLE Orders
(Closed DATE, 
Open DATE,
Plan DATE,
Station Char);


insert into Orders values ("2018-10-23",NULL,NULL, "A");    
insert into Orders values ("2018-10-22",NULL,NULL, NULL);    
insert into Orders values ("2018-10-22",NULL,NULL, "B");    
insert into Orders values ("2018-10-22",NULL,NULL, NULL);    
insert into Orders values (NULL,NULL,"2018-10-23", "C");
insert into Orders values (NULL,NULL,"2018-10-22", NULL);
insert into Orders values (NULL,NULL,"2018-10-22", NULL);

我想用最后一个已知值填充station列,以得到下面所需的结果。

+------------+------+------------+---------+
| Closed     | Open | Plan       | Station |
+------------+------+------------+---------+
| 2018-10-23 | NULL | NULL       | A       |
| 2018-10-22 | NULL | NULL       | A       |
| 2018-10-22 | NULL | NULL       | B       |
| 2018-10-22 | NULL | NULL       | B       |
| NULL       | NULL | 2018-10-23 | C       |
| NULL       | NULL | 2018-10-22 | C       |
| NULL       | NULL | 2018-10-22 | C       |
+------------+------+------------+---------+