你可以使用
itertools.product
:
import itertools
atr = ['a','b','c']
m = ['h','i','j']
func = ['x','y','z']
prod = list(itertools.product(func, m))
result = {i:prod for i in atr}
输出:
{'a': [('x', 'h'), ('x', 'i'), ('x', 'j'), ('y', 'h'), ('y', 'i'), ('y', 'j'), ('z', 'h'), ('z', 'i'), ('z', 'j')], 'b': [('x', 'h'), ('x', 'i'), ('x', 'j'), ('y', 'h'), ('y', 'i'), ('y', 'j'), ('z', 'h'), ('z', 'i'), ('z', 'j')], 'c': [('x', 'h'), ('x', 'i'), ('x', 'j'), ('y', 'h'), ('y', 'i'), ('y', 'j'), ('z', 'h'), ('z', 'i'), ('z', 'j')]}