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尝试在Python3中复制列表时未调用函数

Mathieu • 4 年前 • 247 次点击  

import random

pool_list = ["1m1","2m1","3m1","4m1","5m1","6m1","7m1","8m1","9m1"]

live_wall = []
dead_wall = []

def copyPool():
    live_wall = list(pool_list)


def shuffleWall():
    random.shuffle(live_wall)

copyPool()
shuffleWall()

print(live_wall)
print(pool_list)
print(len(pool_list))
print(len(live_wall))
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247 次点击  
文章 [ 2 ]  |  最新文章 4 年前
alchemist_
Reply   •   1 楼
alchemist_    4 年前

如果不想使用全局变量

  pool_list = ["1m1","2m1","3m1","4m1","5m1","6m1","7m1","8m1","9m1"]

  live_wall = []

  def copyPool():
      live_wall = list(pool_list)
      return live_wall

  live_wall = copyPool()

  print(live_wall)
Loocid
Reply   •   2 楼
Loocid    4 年前

当你使用 live_wall = list(pool_list) 在函数内部,它创建一个同名的局部变量。如果要分配给函数作用域之外的变量,则需要使用 global 关键字。

def copyPool():
    global live_wall
    live_wall = list(pool_list)