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如何在python中简化变量的分数值

Sebastian Przybylski • 5 年前 • 1588 次点击  

我有一个变量叫做 b 谁的价值是这样决定的: b = float(input("What is your y-intercept?")) . 在文件的后面,我想取 (假设它是一个浮点数)并将其转换为如下分数: print(Fraction(b)) . 我知道有点像 print(Fraction(0.45)) 将打印 8106479329266893/18014398509481984 但是 print(Fraction('0.45')) 将打印 9/20 . 我怎么能用一个变量得到同样的结果呢?做 print(Fraction('b')) 给我这个错误: ValueError: Invalid literal for Fraction: 'b' .

代码:

from fractions import Fraction

elif equation == 'slope':    
    slope = input("Do you need to find slope? Type 'yes' or 'no'.")

    if slope == 'yes':
       y2 = float(input("What's your y2 value?:"))
       y1 = float(input("What is your y1 value?"))
       x2 = float(input("What is your x2 value?:"))
       x1 = float(input("What is your x1 value?:"))

        m = y2-y1/x2-x1
        print(str(m))
    elif slope == 'no':
        m = input("What is the slope?")

    b = float(input("What is your y-intercept?"))
    m = str(m)
    b = str(b)
    print("Your equation is: y = {}x + {}".format(m,b))
    simplify = input("Do you want to simplify this to standard form? Type in 'yes' or 'no'")

    if simplify == 'yes':
        m = float(m)
        b = float(b)
        if m < 0:
            pos_m = m*-1
        if isinstance(b, float):
            print(Fraction(b)) #Works, but not what I want
            print(Fraction('b')) #Does not work 
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