在python中获取所有%(name)的占位符

似乎是个很好的用途 re.findall

>>> import re
>>> string = "This is a %(name)s example string %(foo)s I would like %(bar)s to extract all the placeholders from %(place)s"
>>> re.findall(r'%\((.+?)\)', string)
['name', 'foo', 'bar', 'place']

%\((.+?)\) %( ,以下一个结尾 ) ,捕获中间的所有内容。

使用正则表达式。

前任:

import re

s = "This is a %(name)s example string %(foo)s I would like %(bar)s to extract all the placeholders from %(place)s"
print(re.findall(r"%\((.*?)\)", s))
# --> ['name', 'foo', 'bar', 'place']