Csv排序和删除python

192.168.136.192,2848,100.100.100.212,6667,"other"
100.100.100.212,6667,192.168.136.192,2848,"other"
100.100.100.212,6667,192.168.136.192,2848,"CHAT IRC message"
192.168.61.74,4662,69.192.30.179,80,"other"
192.168.107.87,4662,69.192.30.179,80,"other"
192.168.107.87,4662,69.192.30.179,80,"infection"
192.168.177.85,4662,69.192.30.179,80,"infection"
192.168.177.85,4662,69.192.30.179,80,"other"
192.168.118.168,4662,69.192.30.179,80,"infection"
192.168.118.168,4662,69.192.30.179,80,"other"
192.168.110.111,4662,69.192.30.179,80,"infection"

到目前为止我已经可以删除副本了现在我需要删除还有src=src&dest=dest | |;src=dest&dest=source&删除带有“other”的那些,如果它们的=被标记为“infected” 这就是我目前为止要移除的复制品

with open(r'alerts.csv','r') as in_file, open('alertsfix.csv','w') as     out_file:
seen = set() # set for fast O(1) amortized lookup
for line in in_file:
    if line in seen: continue # skip duplicate

    seen.add(line)
    out_file.write(line)

src/prt/dest/prt/msg
1. a/a1/b/b1/c
2. 2a/2a1/2b/2b1/2c

条件:

if a==2b && a1==2b1 && b==2a && b1==2a1 c==2c
    delete one of them being they are equal

或

if a==2b && a1==2b1 && b==2a && b1==2a1  ( c==other ) &&( 2c=="infected" || 2c=='CNC") 
    delete one that has message "other"