not_speshal

不要在适当的位置修改字符串。相反,只需创建一个新字符串:

output = ""
for char in camel_case:
    if char.isupper():
        output += "_"
    output += char.lower()

或者,用一句话来说:

"".join("_"+char.lower() if char.isupper() else char.lower() for char in camel_case)

您可以检查“float”、“string”模式,并相应地追加:

output = list()
for i, element in enumerate(arr):
    if isinstance(element, float) and isinstance(arr[i+1], str):
        if isinstance(arr[i+2], str):
            t = tuple(arr[i:i+3])
        else:
            t = tuple(arr[i:i+2]+["NONE"])
        output.append(t)

>>> output
[(1150.1, 'James', 'NONE'),
 (3323.1, 'Steve', 'NONE'),
 (9323.1, 'John', 'NONE'),
 (1233.1, 'Gary', 'criminal'),
 (3293.1, 'Josh', 'NONE'),
 (9232.1, 'Daniel', 'criminal')]

IIUC,你可以试试 pivot :

df["Ratio"] = df["Data A"].div(df["Data B"])

output = df.drop("Ratio", axis=1).join(df.pivot(None, "Place", "Ratio").mul(100).fillna(0).add_prefix("To "))

>>> output
     Place  Data A  Data B  Data C  To England  To France
0   France    0.03    0.06    0.15    0.000000       50.0
1  England    0.05    0.07    0.11   71.428571        0.0
2  England    0.04    0.03    0.87  133.333333        0.0

尝试创建一个字典,将账号映射到VPC。然后转换这本字典:

dct = dict()
for vpc in vpcs:
    if vpc["ResourceOwnerId"] not in dct:
        dct[vpc["ResourceOwnerId"]] = list()
    dct[vpc["ResourceOwnerId"]].append(vpc["ResourceId"])

output = [{"account_number": k, "vpc": v} for k,v in dct.items()]

>>> output
[{'account_number': '111111111111', 'vpc': ['vpc-aaaaa', 'vpc-ddddd']},
 {'account_number': '222222222222', 'vpc': ['vpc-ccccc']}]

尝试:

>>> [[0 for i in range(len(mat[0]))] for j in range(len(mat))]
[[0], [0], [0], [0], [0]]

也最好使用不同的循环变量,而不是 i 对于这两种情况:

首先将日期转换为时间戳:

import pandas as pd
df["date"] = pd.to_datetime(df["date"], format="%m/%d/%y")
>>> df["date"].max()

尝试:

words = list()
with open("file.txt", errors="ignore") as infile:
    for row in infile:
        for word in row.split():
            if word.strip('"(.,!?):').replace("'","").replace("-","").isalpha():
                words.append(word.strip('"(.,!?):').lower())

>>> " ".join(words)
'zwizwai confirmed that there were attempts to place him together with mudzuri on the sanctions list describing them as nicodimous by some fellow mdc-t the cast in order of appearance on universities to ensure the safety of women on'

尝试:

grid = [[[i,j] for j in range(colRange)] for i in range(rowRange)]

>>> grid
[[[0, 0], [0, 1]], [[1, 0], [1, 1]], [[2, 0], [2, 1]]]