这样比较好
np.vectorize
:
format_number = lambda n: n if n % 1 else int(n)
for count, formater in enumerate([a, b, c]):
formater[formater < 0] = 0
formatter = np.vectorize(format_number)(formater)
print(formater.tolist())
要修复代码,请执行以下操作:
format_number = lambda n: n if n % 1 else int(n)
for count,formater in enumerate([a, b, c]):
formater = list(map(lambda n: 0 if n < 0 else format_number(n), formater))
print(formater)
两种输出:
[2323, 34, 12, 0, 12, 4, 0, 0, 0, 11, 0]
[12, 0, 0, 0, 0]
[23, 45, 3, 13, 0, 5]
