Python——如何只从中间有逗号的字符串中获取数字

如果保证初始字符串始终具有相同的格式, 前缀+值,为什么不把这个子串出来,一个简单的 stringA, stringB = stringA[len(prefixA):], stringB[len(prefixB):]; 然后, list1, list2 = [int(num) for num in stringA.split(',')], [int(num) for num in stringB.split(',')]; 我应该做这项工作。。。

# Add regex package
import re

stringA = "values-are-10,20,30,40,50"
stringB = "values-are-10"
#search using regex
A = re.findall('[0-9]+', stringA)
print(A) # ['10', '20', '30', '40', '50']
B = re.findall('[0-9]+', stringB)
print(B) # ['10']

[int(v) for v in stringA.rsplit("-", 1)[-1].split(",")]

rsplit 从右侧拆分-所有数字都显示在最后一个数字之后 "-" .然后我们 split 通过 ","

使用 re.findall 这是你的朋友:

stringA = "values-are-10,20,30,40,50"
stringB = "values-are-10"
strings = [stringA, stringB]
output = [re.findall(r'\d+(?:,\d+)*', s)[0] for s in strings]
print(output)  # ['10,20,30,40,50', '10']