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如何获取当前登录用户?Django模型

Manas S. Roy • 4 年前 • 2110 次点击  

我想让当前登录的用户访问这个CreateForm表单。下面是我的当前代码,这里是我的请求。用户没有给我错误

ValueError位于/创建帖子/ 无法分配“<SimpleLazyObject:<用户:testuser>”:“Post.author”必须是“author”实例。

模型。py

class Author(models.Model):
   user = models.OneToOneField(User, on_delete=models.CASCADE)
   rate = models.IntegerField(default=0)
 
class Post(models.Model):
    title = models.CharField(max_length= 50)
    overview = models.TextField()
    body_text = RichTextUploadingField(null = True)
    time_upload = models.DateTimeField(auto_now_add=True)
    author = models.ForeignKey(Author, related_name='author', on_delete=models.CASCADE)
    thumbnail = models.ImageField(upload_to = 'thumbnails')
    publish = models.BooleanField()
    categories = models.ManyToManyField(Categories)
    read = models.IntegerField(default=0)
    slug = models.SlugField(null= True, blank= True)

形式。py

class CreateForm(ModelForm):
class Meta:
    model = Post
    fields = [
        'title',
        'overview',
        'body_text',
        'thumbnail',
        'categories',
        'publish',
    ]

意见。py

def create_post(request):
if request.method == 'POST':
    form = CreateForm(request.POST, request.FILES)
    if form.is_valid:
        post = form.save(commit=False)
        post.author= request.user
        post.save()
        return render(request, 'index.html')
else:
    form = CreateForm()
return render(request, 'create_post.html', {'form': form})
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