python:解析以冒号分隔的格式化字符串

创建一个 iterator 在你的绳子上:

message = '1:4:a:5:6:7:2:10:72:75:63:6f:6e:74:72:6f:6c:6c:65:72:2e:6f:72:67'

code = iter(message.split(':'))
data = {}

for t in code:
    l = int(next(code), 16)
    d = [next(code) for _ in range(l)]
    data[t] = d

输出:

>>> data
{'1': ['a', '5', '6', '7'],
 '2': ['72', '75', '63', '6f', '6e', '74', '72', '6f', '6c', '6c', '65', '72', '2e', '6f', '72', '67']}

像这样的方法应该有用:

ss = "1:4:a:5:6:7:2:10:72:75:63:6f:6e:74:72:6f:6c:6c:65:72:2e:6f:72:67".split(":")

d = {}
idx = 0
while idx < len(ss):
    key = ss[idx]
    idx += 1
    length = int(ss[idx])
    idx += 1
    arr = ss[idx:idx+length]
    d[key] = arr
    idx += length

输出 d :

{'1': ['a', '5', '6', '7'],
 '2': ['72', '75', '63', '6f', '6e', '74', '72', '6f', '6c', '6c'],
 '65': ['2e', '6f', '72', '67']}