我有这样的情况:
str1 = "cat, dog, rat" print( ("cat" not in str1) and ("dog" not in str1) and ("rat" not in str1)) #1 print(any(x not in str1 for x in ("cat","dog","rat"))) #2
问题是,如果我添加任何其他语句,那么#1条件太长,所以我将其转换为#2,但是#2返回相反的结果,那么如何简单地用Python编写#1呢?
