考虑序列的Python中重复值的计数

这个 itertools.groupby 函数是最受欢迎的,但也许未来的读者会喜欢一种算法来实际查找这些分组:

def groups(*items):
    i = 0
    groups = []
    while i < len(items):
        item = items[i]
        j = i + 1
        count = 1
        while j < len(items):
            if items[j] == item:
                count += 1
                j += 1
            else:
                break
        i = j
        groups.append((item, count))
    return groups

不能在dict中存储重复的键。如果您愿意拥有元组列表,可以使用 itertools.groupby :

from itertools import groupby

lst = ['asd', 'abb', 'das', 'fab', 'abb', 'abb']

counts = [(k, len([*g])) for k, g in groupby(lst)]
print(counts) # [('asd', 1), ('abb', 1), ('das', 1), ('fab', 1), ('abb', 2)]