如果用户输入字符串为空、数字或具有非ASCII python

Sheikh Rahman • 6 年前 • 1453 次点击

当用户输入名字时,如果它是空白的、有数字、字母数字或有非ASCII字符,我不会将它插入数据库。

下面的代码不接受有效输入,只有使用 len 和 isDigit 这两个条件。

while (len(f_name) == 0  or f_name.isdigit()

或

f_name.encode('ascii',errors='ignore') or f_name.isalnum()):

Create new user: Y/N ?y
Enter first name: ui
First name cannot be empty or have numeric values

有人能解释一下如何解决这个问题吗?谢谢你的时间。其余代码如下:

import sqlite3

#connect a built in function to connect or create db
conn=sqlite3.connect('phonebook.db')

#Create a cursor function which allows us to do sql operations
crsr=conn.cursor()

#This function to check if table exists
def create_Table():
    #Check if the table exists or not
    crsr.execute("SELECT name FROM sqlite_master WHERE name='phonebook'")
    tableSize=len(crsr.fetchall())#will be greater than 0 if table exists
    if tableSize>0:
        print()
    else:
        #create the table
        crsr.execute(""" Create Table phonebook(
                    FirstName text NOT NULL,
                    LastName text,
                    Phone text PRIMARY KEY NOT NULL)
                   """)

        #check if table got created or not
        crsr.execute("SELECT name FROM sqlite_master WHERE name='phonebook'")
        tableSize = len(crsr.fetchall())  # will be greater than 0 if table exists
        if tableSize > 0:
            print('Table was created successfully')

#This function will create new users and insert in DB
def create_User():
    try:
        while True:
            rsp = input('Create new user: Y/N ?')
            if rsp == 'y':
                f_name = input('Enter first name: ')
                # First name cannot be empty or have numeric values
                while (len(f_name) == 0  or f_name.isdigit() or f_name.encode('ascii',errors='ignore') or f_name.isalnum()):
                    print('First name cannot be empty or have numeric values')
                    f_name = input('Enter first name: ')
                l_name = input('Enter last name: ')
                phone = input('Enter phone number: ')
                crsr.execute("INSERT INTO phonebook VALUES (:FirstName, :LastName, :Phone)",
                             {'FirstName': f_name, 'LastName': l_name, 'Phone': phone})
                conn.commit()
            if rsp == 'n':
                break
    except:
     print('UNIQUE constraint failed: phone number already exists')

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1453 次点击

文章 [ 2 ] | 最新文章 6 年前

• 1 楼

vahdet 6 年前

使用 isalpha 要确保字符串仅为字母:

f_name = input('Enter first name: ')
if f_name and f_name.isalpha():
  # your ACCEPTED logic here

此外,如果您需要检查这些字母是否为ASCII码,您可以将它们的编码长度与它们自己进行比较:

f_name = input('Enter first name: ')
if f_name and f_name.isalpha() and len(f_name) == len(f_name.encode()):
  # your ACCEPTED logic here

编辑增加了空字符串检查(即 if f_name )

• 2 楼

Arne 6 年前

如果您熟悉正则表达式,可以按以下方式测试条件“不得为空”和“不得包含数字”:

import re

# match one or more characters that range from a to z or A to Z
username_check = re.compile(r'[a-zA-Z]+')

...
while True:
  if rsp == 'y':
    f_name = input('Enter first name: ')
    while not username_check.fullmatch(f_name):
      print('First name cannot be empty or have numeric values')
      f_name = input('Enter first name: ')

正则表达式的好处在于,您可以非常灵活地扩展当前的最小解决方案,以测试非常特定的模式:

import re

# allow unicode word characters
allowed = re.compile(r'\w+')
# numbers are still not allowed
forbidden = re.compile(r'\d')

while True:
    f_name = input('Enter first name: ')
    while not (allowed.fullmatch(f_name) and not forbidden.search(f_name)):
      print('First name cannot be empty or have numeric values')
      f_name = input('Enter first name: ')

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