这里是一个初学Python编程的学习者。
我正在用python制作一个非常简单的两位数计算器。虽然它运行得很好,但我无法解决以“.0”结尾的浮点数问题。我想删除这个结尾。我试了几次,但都不管用。我需要在代码中添加什么条件?你能看一下下面吗?
def calculator():
num1 = float(input('First number: '))
operator = input('+, -, / or * ? ')
num2 = float(input('Second Number: '))
if operator == '+':
return print(num1, '+', num2, '=', num1 + num2)
elif operator == '-':
return print(num1, '-', num2, '=', num1 - num2)
elif operator == '/':
return print(num1, '/', num2, '=', num1 / num2)
elif operator == '*':
return print(num1, '*', num2, '=', num1 * num2)
calculator()
提前谢谢!
我完全按照@water winter的建议做了,但每当我执行程序并输入数字和运算符时,就会出现以下错误:
if result.is_integer():
AttributeError: 'int' object has no attribute 'is_integer'
更新:看起来只有“/”操作符工作得很好。其他3个操作符给出了上述相同的错误。:
新的更新:最后我设法使计算器编程完美!
def calculator():
num1 = float(input("First number: "))
operator = input("Choose: +, -, /, or *")
num2 = float(input("Second number: "))
num1 = int(num1) if num1.is_integer() else num1
num2 = int(num2) if num2.is_integer() else num2
add = (num1 + num2)
subtract = (num1 - num2)
divide = (num1 / num2)
multiply = (num1 * num2)
if operator == "+" and add % 1 == 0:
print(num1, "+", num2, "is equal to:", int(add))
elif operator == "+" and not add % 1 == 0:
print(num1, "+", num2, "is equal to:", add)
elif operator == "-" and subtract % 1 == 0:
print(num1, "-", num2, "is equal to:", int(subtract))
elif operator == "-" and not subtract % 1 == 0:
print(num1, "-", num2, "is equal to:", subtract)
elif operator == "/" and divide % 1 == 0:
print(num1, "/", num2, "is equal to:", int(divide))
elif operator == "/" and not divide % 1 == 0:
print(num1, "/", num2, "is equal to:", divide)
elif operator == "*" and multiply % 1 == 0:
print(num1, "*", num2, "is equal to:", int(multiply))
elif operator == "*" and not multiply % 1 == 0:
print(num1, "*", num2, "is equal to:", multiply)
calculator()
谢谢你们的帮助和建议。他们帮了很多忙!:)
