在python中将字符串值拆分为整数

muhammet daÄaÅan • 6 年前 • 1304 次点击

我这里有一些不同的号码。每次都会改变。我需要创建一个多维数组
array[x][y] = & gt; x 应包括之前拆分的值 , 和 y 应该包括 ' ' 空的。
我该怎么做?谢谢您。

dat.xyz
2,3,4,5,6,7,8,9 2,3,4,5,6,7,8,9 2,3,4,5,6,7,8,9 2,3,4,5,6,7,8,9

output = open('dat.xyz', 'r') # See the r
output_list = output.read().strip().split(',')

我以前能找到号码 , 但它只显示在一行中。但是,我想从多维的角度来做。它应该将维度拆分为空 ’ . 谢谢您。

输出应遵循

[[2, 3, 4, 5, 6, 7, 8, 9], 
[2, 3, 4, 5, 6, 7, 8, 9], 
[2, 3, 4, 5, 6, 7, 8, 9], 
[2, 3, 4, 5, 6, 7, 8, 9]]

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1304 次点击

文章 [ 2 ] | 最新文章 6 年前

• 1 楼

Paresh 7 年前

import numpy as np

# read file and split over whitespace
with open('dat.xyz', 'r') as f:
    rows = f.read()
    rows = rows.split(' ')

arr = []

# split each value in row over comma, then convert each element to integer
for row in rows:
    row = row.split(',')
    for i in range(len(row)):
        row[i] = int(row[i])
    arr.append(row)

# convert to array
arr = np.array(arr)

arr

输出:

array([[2, 3, 4, 5, 6, 7, 8, 9],
       [2, 3, 4, 5, 6, 7, 8, 9],
       [2, 3, 4, 5, 6, 7, 8, 9],
       [2, 3, 4, 5, 6, 7, 8, 9]])

• 2 楼

Eric Duminil 7 年前

您应该首先围绕空格拆分以获取行,然后迭代这些行以获取单元格:

>>> rows = "2,3,4,5,6,7,8,9 2,3,4,5,6,7,8,9 2,3,4,5,6,7,8,9 2,3,4,5,6,7,8,9".split(' ')
>>> rows
['2,3,4,5,6,7,8,9', '2,3,4,5,6,7,8,9', '2,3,4,5,6,7,8,9', '2,3,4,5,6,7,8,9']
>>> [row.split(',') for row in rows]
[['2', '3', '4', '5', '6', '7', '8', '9'], ['2', '3', '4', '5', '6', '7', '8', '9'], ['2', '3', '4', '5', '6', '7', '8', '9'], ['2', '3', '4', '5', '6', '7', '8', '9']]

您还可以将这些单元格转换为整数:

>>> [[int(cell) for cell in row.split(',')] for row in rows]
[[2, 3, 4, 5, 6, 7, 8, 9], [2, 3, 4, 5, 6, 7, 8, 9], [2, 3, 4, 5, 6, 7, 8, 9], [2, 3, 4, 5, 6, 7, 8, 9]]

还是让 numpy 为您进行转换:

>>> import numpy as np
>>> np.array([row.split(',') for row in rows], np.int)
array([[2, 3, 4, 5, 6, 7, 8, 9],
       [2, 3, 4, 5, 6, 7, 8, 9],
       [2, 3, 4, 5, 6, 7, 8, 9],
       [2, 3, 4, 5, 6, 7, 8, 9]])

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