我觉得这个问题很简单,但我不知道该怎么做。
我有一个从1到8的编号规则的xpath元素。我需要一个接一个地把它们全部打开。
//*[@id="meio"]/div[2]/section/article[1]/h2/span/a[1]
//*[@id="meio"]/div[2]/section/article[2]/h2/span/a[1]
//*[@id="meio"]/div[2]/section/article[3]/h2/span/a[1]
//*[@id="meio"]/div[2]/section/article[4]/h2/span/a[1]
//*[@id="meio"]/div[2]/section/article[5]/h2/span/a[1]
//*[@id="meio"]/div[2]/section/article[6]/h2/span/a[1]
//*[@id="meio"]/div[2]/section/article[7]/h2/span/a[1]
//*[@id="meio"]/div[2]/section/article[8]/h2/span/a[1]
我试着这么做:
while w > 0:
i = 0
a = str(i)
while i < 8:
i += 1
driver.find_element_by_xpath('//*[@id="meio"]/div[2]/section/article[" + str(i) + "]/h2/span/a').click()
driver.refresh()
#there's more code after this, but I don't think it's necessary.
但是它做了我在第一页需要做的事情,然后又回到第一页,在第一页中一直循环。我不能单击xpath 2或除1之外的任何其他项。我做错什么了?
每次循环开始时,我都需要在xpath中增加一个数字,我该怎么做呢?
