min(x,y)
^
max(x,y)
x = ['a', 'b', 'c']
y = [1, 2, 3]
combos = get_combos(x,y)
for combo in combos:
print(combo)
…我想写
get_combos(x, y)
这样它会返回一个包含27个组合对的列表,打印时,这些组合对如下所示:
[('a', 1) ('a', 2) ('a', 3)]
[('a', 1) ('a', 2) ('b', 3)]
[('a', 1) ('a', 2) ('c', 3)]
[('a', 1) ('b', 2) ('a', 3)]
[('a', 1) ('b', 2) ('b', 3)]
[('a', 1) ('b', 2) ('c', 3)]
[('a', 1) ('c', 2) ('a', 3)]
[('a', 1) ('c', 2) ('b', 3)]
[('a', 1) ('c', 2) ('c', 3)]
[('b', 1) ('a', 2) ('a', 3)]
[('b', 1) ('a', 2) ('b', 3)]
[('b', 1) ('a', 2) ('c', 3)]
[('b', 1) ('b', 2) ('a', 3)]
[('b', 1) ('b', 2) ('b', 3)]
[('b', 1) ('b', 2) ('c', 3)]
[('b', 1) ('c', 2) ('a', 3)]
[('b', 1) ('c', 2) ('b', 3)]
[('b', 1) ('c', 2) ('c', 3)]
[('c', 1) ('a', 2) ('a', 3)]
[('c', 1) ('a', 2) ('b', 3)]
[('c', 1) ('a', 2) ('c', 3)]
[('c', 1) ('b', 2) ('a', 3)]
[('c', 1) ('b', 2) ('b', 3)]
[('c', 1) ('b', 2) ('c', 3)]
[('c', 1) ('c', 2) ('a', 3)]
[('c', 1) ('c', 2) ('b', 3)]
[('c', 1) ('c', 2) ('c', 3)]
我已经看过itertools.combinations、itertools.product和itertools.permutations,但它们似乎都没有给我确切的我要找的东西。itertools.permutations与
zip
this answer
),但是结果列表是互斥的,因为两个列表中的任何元素都不能在单个组合中重复(例如。
[('a', 1), ('a', 2), ('c', 3)]
