如果“根”总是相同的,你可以用正则表达式来捕获它们。
有了这个解决方案
更改原始列表
.
import re
l = [(0.14409883378622257, 'count_90'),
(0.1274820635854658, 'count_60'),
(0.10362930186446877, 'count_30'),
(0.017066033814948037, 'country_code_destination_ID'),
(0.014104260612047153, 'country_code_destination_US'),
(0.011414953372550486, 'SACC_MARKET_SEGMENT_BDZ'),
(0.010291762087645236, 'leading_bu_PP'),
(0.009979426898654558, 'SACC_MARKET_SEGMENT_IT3')]
country_code_value = 0
sacc_market_value = 0
# Loop on the list with indexes and increment values when catch regex pattern.
for i, t in enumerate(l):
if re.search(r"country_code_destination", t[1]):
# remove the element of the list and keep value in variable
country_code_value += l.pop(i)[0]
elif re.search(r"SACC_MARKET_SEGMENT", t[1]):
# remove the element of the list and keep value in variable
sacc_market_value += l.pop(i)[0]
# Make tuples
country_code_destination = (country_code_value, "country_code_destination")
sacc_market_segment = (sacc_market_value, "SACC_MARKET_SEGMENT")
# And append to the original list
l.append(country_code_destination)
l.append(sacc_market_segment)
