使用列表理解:
L1 = [('G', 'T'), ('T', 'T'), ('T', 'U'), ('U', 'I'), ('I', 'P')]
L2 = [('E', 'G'), ('G', 'T'), ('T', 'P')]
indices = [[L1.index(s),i] for i, s in enumerate(L2) if s in L1]
# print the first match (in this case there is only one match)
print(indices[0])
[0, 1]
解释
[[L1.index(s),i] for i, s in enumerate(L2) if s in L1]
:
-
for i, s in enumerate(L2)
:i是二级元组元素中的索引
-
if s in L1
:这将检查当前
s
也在L1
-
[L1.index(s),i]
:返回索引列表
附言:对于复制品,这可能表现不好。
