Emi OB

如果列表仅包含0或5,则可以在for循环中对列表求和,并将最终结果除以5以获得计数:

x=[0,5,5,5,0,0,0,5,0,5,0,0]
count = 0
for i in x:
    count += i
count = count/5

输出:

5

要返回最长元素的列表,请执行以下操作:

c = [a[i] if len(a[i]) > len(b[i]) else b[i] for i in range(len(b))]
['AAAA', 'FFF', 'GGGG', 'DDDDD']

对于每个索引的最大长度,下面返回所需列表:

d = [max(len(a[i]), len(b[i])) for i in range(len(b))]
[4, 3, 4, 5]