转换Python字典中列表值的元素

A. similar question 我已经检查过了! 你也可以这样做:

a = [{'point1': ['20.900', '15.300', '20.400'], 'point2': ['0.600', '34.700', '8.100'], 'point3': ['12.100', '15.800', '2.300'], 'point4': ['15.000', '5.800', '16.900']}]
[{k : list(map(float, v))  for k, v in i.items() } for i in a]

array=[{'point1': ['20.900', '15.300', '20.400'], 'point2': ['0.600', '34.700', '8.100'], 'point3': ['12.100', '15.800', '2.300'], 'point4': ['15.000', '5.800', '16.900']}]
new_array=array[0]

for i in new_array.values():
    k=0
    for j in i:
        i[k]=int(float(j))
        k=k+1
        
print(new_array)

试着用一句话来说:

l = [{'point1': ['20.900', '15.300', '20.400'], 'point2': ['0.600', '34.700', '8.100'], 'point3': ['12.100', '15.800', '2.300'], 'point4': ['15.000', '5.800', '16.900']}]

result = [{k: [int(float(i)) for i in v] for k, v in l[0].items()}]

结果将是:

[{'point1': [20, 15, 20],
  'point2': [0, 34, 8],
  'point3': [12, 15, 2],
  'point4': [15, 5, 16]}]

你可以使用一个循环:

for d in lst:
    for v in d.values():
        for i, num in enumerate(v):
            v[i] = int(float(num))

print(lst)

输出:

[{'point1': [20, 15, 20],
  'point2': [0, 34, 8],
  'point3': [12, 15, 2],
  'point4': [15, 5, 16]}]