A.
similar question
我已经检查过了!
你也可以这样做:
a = [{'point1': ['20.900', '15.300', '20.400'], 'point2': ['0.600', '34.700', '8.100'], 'point3': ['12.100', '15.800', '2.300'], 'point4': ['15.000', '5.800', '16.900']}]
[{k : list(map(float, v)) for k, v in i.items() } for i in a]
