Python-列表的平方根

也许是这个?

# Use this import for all examples
from math import sqrt

old = [1,2]
new = [sqrt(x) for x in old]

函数形式

def sqrt_list(old):
    return [sqrt(x) for x in old]

或

def sqrt_list(old):
    new_list = []

    for i in old:
        new_list.append(sqrt(i))

    return new_list

哪里:

print(sqrt_list([11, 22, 33]))

产出:

[3.3166247903554, 4.69041575982343, 5.744562646538029]