在python列表中只创建相同的对

如果我没听错的话,你可以选择列表并创建所有可能的配对。 要做到这一点,你应该使用itertools。

请看以下主题: How to split a list into pairs in all possible ways .

import itertools
list(itertools.combinations(range(6), 2))
#[(0, 1), (0, 2), (0, 3), (0, 4), (0, 5), (1, 2), (1, 3), (1, 4), (1, 5), (2, 3), (2, 4), (2, 5), (3, 4), (3, 5), (4, 5)]

它将使用移动光标进行切片以获取值。

def func(l):
    prev_i, i = 0, 2
    while True:
        current = l[prev_i: i]
        if len(current) < 2:
            break
        yield current
        prev_i, i = i, i + 2


print(list(func([1,2,3,4,5,6,7])))

输出:

[[1, 2], [3, 4], [5, 6]]

你可以这样做:

list = [1,2,3,4,5,6,7]
def chunks(lst, n):
    """Yield successive n-sized chunks from lst."""
    for i in range(0, len(lst), n):yield lst[i:i + n]    
sublist = [x for x in chunks(list, 2)]
for x in sublist:
    if x.__len__() > 1:continue
    else:sublist.remove(x)
print(sublist)

输出:

[[1,2],[3,4],[5,6]]

你可以用 zip 并以不同的起点,每两项对输入列表进行切片:

lst = [1,2,3,4,5,6,7]

list(zip(lst[::2], lst[1::2]))

输出: [(1, 2), (3, 4), (5, 6)]