pppig

它将使用移动光标进行切片以获取值。

def func(l):
    prev_i, i = 0, 2
    while True:
        current = l[prev_i: i]
        if len(current) < 2:
            break
        yield current
        prev_i, i = i, i + 2


print(list(func([1,2,3,4,5,6,7])))

输出:

[[1, 2], [3, 4], [5, 6]]

如果是绑定一个对象,这是否能简单快速地满足您的需求。

object.__setattr__

尝试属性分配时调用。它被调用,而不是正常的机制(即将值存储在实例字典中)。name是属性名,value是要分配给它的值。

class foo:
    name: str = ""
    last_name: str = ""


class other:
    def __init__(self, obj):
        self.__dict__["obj"] = obj

    def __setattr__(self, key, value):
        if not hasattr(self, key) and hasattr(self.__dict__["obj"], key):
            setattr(self.__dict__["obj"], key, value)
        else:
            super().__setattr__(key, value)


f = foo()
o = other(f)
print("1. ", f.name, f.last_name)
o.name = "Jon"
print("2. ", f.name, f.last_name)

"""
1.   
2.  Jon 
"""