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关于python递归的困惑

jayl151 • 6 年前 • 1204 次点击  

我在写一个递归函数来解决一个问题,在这个问题中,你需要找到所有的组合,以达到给定数字的目标和,并且每个数字都小于某个限制。

我写的代码如下:

results = []

def findSchedulesHelper(workHours_left, dayHoursLimit, days_left, res):
    if workHours_left < 0:
        return
    elif workHours_left > 0 and days_left == 0:
        return
    elif workHours_left == 0 and days_left != 0:
        for i in range(days_left):
            res.append(0)
        results.append(res)
        return
    elif days_left == 0 and workHours_left == 0:
        results.append(res)
        return
    else:
        for i in range(dayHoursLimit + 1):
            res.append(i)
            findSchedulesHelper(workHours_left - i, dayHoursLimit, days_left - 1, res)
            res.pop()


def findSchedules(workHours, dayHours, pattern):
    # Write your code here
    num_question_mark = 0
    total_hours_so_far = 0
    for char in pattern:
        if char == "?":
            num_question_mark += 1
        else:
            total_hours_so_far += int(char)

    hours_left_to_fill = workHours - total_hours_so_far

    for i in range(dayHours + 1):
        findSchedulesHelper(hours_left_to_fill - i, dayHours, num_question_mark - 1, [i])
    print results

findSchedules(3,2,"??2??00")

但这给出了错误的答案。

如果我更改一行并使其成为:

results = []

def findSchedulesHelper(workHours_left, dayHoursLimit, days_left, res):
    if workHours_left < 0:
        return
    elif workHours_left > 0 and days_left == 0:
        return
    elif workHours_left == 0 and days_left != 0:
        for i in range(days_left):
            res.append(0)
        results.append(res)
        return
    elif days_left == 0 and workHours_left == 0:
        results.append(res)
        return
    else:
        for i in range(dayHoursLimit + 1):
            findSchedulesHelper(workHours_left - i, dayHoursLimit, days_left - 1, res + [i])


def findSchedules(workHours, dayHours, pattern):
    # Write your code here
    num_question_mark = 0
    total_hours_so_far = 0
    for char in pattern:
        if char == "?":
            num_question_mark += 1
        else:
            total_hours_so_far += int(char)

    hours_left_to_fill = workHours - total_hours_so_far

    for i in range(dayHours + 1):
        findSchedulesHelper(hours_left_to_fill - i, dayHours, num_question_mark - 1, [i])
    print results

findSchedules(3,2,"??2??00")

那么一切都是正确的。我真的很困惑为什么会这样。我试着做了一些调试,发现append和pop并不像我期望的那样工作。如果有人能解释我做这个函数的两种方法之间到底有什么区别,那就太好了。

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