如何定义类似regex的:包括字母和(),但不包括。和使用python的数字

如果您将包括字母()和空格,那么它将自动排除其他元素。

import re

myTry = ['aa bb Aas','aa 1 Aasdf','aa bb (cc) AA','aa ASD','aa . ASD']

for item in myTry:
    if re.match('[a-z() ]*A', item):
        print(item)

您可以使用两个regex操作。第一个通过匹配 ^[a-zA-Z\s\(\)]*$ ,然后第二个使用正向先行收集所需子字符串: .*?(?= [A-Z]) .

import re

my_try = ['a bb Aas','aa 1 Aasdf','aa bb (cc) AA','aaa ASD','aa . ASD','aaaa 1 bb Aas']
filtered = [x for x in my_try if re.match(r'^[a-zA-Z\s\(\)]*$', x)]
result = [re.match(r'.*?(?= [A-Z])', x).group(0) for x in filtered]

print(result) # => ['a bb', 'aa bb (cc)', 'aaa']

如果预期某些字符串可能会通过筛选(即,包含除字母字符、括号或空格之外的其他内容),但可能与lookahead不匹配,则需要筛选中间结果:

import re

my_try = ['a bb Aas','aaa ASD','aa . ASD','aaaa 1 bb Aas', '']
#                                                          ^^ could cause problems
filtered = [x for x in my_try if re.match(r'^[a-zA-Z\s\(\)]*$', x)]
matches = [re.match(r'.*?(?= [A-Z])', x) for x in filtered]
result = [x.group(0) for x in matches if x]

print(result) # => ['a bb', 'aaa']