仅打印.txt文件中的特定单词-Python

如对下列问题有任何帮助,将不胜感激。

我有一个名为DOB的.txt文件:

Orville Wright 21 July 1988
Rogelio Holloway 13 September 1988
Marjorie Figueroa 9 October 1988
Debra Garner 7 February 1988
Tiffany Peters 25 July 1988
Hugh Foster 2 June 1988
Darren Christensen 21 January 1988
Shelia Harrison 28 July 1988
Ignacio James 12 September 1988
Jerry Keller 30 February 1988
Frankie Cobb 1 July 1988
Clayton Thomas 10 December 1988
Laura Reyes 9 November 1988
Danny Jensen 19 September 1988
Sabrina Garcia 20 October 1988
Winifred Wood 27 July 1988
Juan Kennedy 4 March 1988
Nina Beck 7 May 1988
Tanya Marshall 22 May 1988
Kelly Gardner 16 August 1988
Cristina Ortega 13 January 1988
Guy Carr 21 June 1988
Geneva Martinez 5 September 1988
Ricardo Howell 23 December 1988
Bernadette Rios 19 July 1988

我需要按以下格式打印所有姓名和出生日期示例:

Name: Â  
O Wright

Birthdate:
21 July 1988

下面的代码按我的需要打印出了大写的第一个字符,但是我如何在以后将特定的单词分开并从txt文件中打印出来呢?

我目前掌握的代码是:

f = open('DOB.txt', 'r+')
for line in f:
    f = line[0] + ". "
    print(f)
g = open('DOB.txt')
for g in g.read().split():
    print(g)

with open('test.txt') as my_file: for person in my_file: first, last, *dob = person.rstrip().split() print(f"Name: {first[0]}. {last}") print(f"Birthdate: {' '.join(dob)}")