将字符串转换为数组中的python

我想最简单的方法是:

my_list = [["", "", "", ""], ["", "2", "", ""], ["", "", "", ""], ["2", "", "", ""]]
my_new_list = []

for a_list in my_list:
    my_new_list.extend(a_list)

for item in my_new_list:
    print(item)

输出为:

2






2

您可以迭代列表并使用 append 而不是使用 extend :

my_list = [["", "", "", ""], ["", "2", "", ""], ["", "", "", ""], ["2", "", "", ""]]
my_new_list = []

for a_list in my_list:
    for item in a_list:
        my_new_list.append(item)

for item in my_new_list:
    print(item)

正如扎克提到的,你可以看到更多的例子 here (How to make a flat list out of list of lists?)

我不知道你到底在问什么,但如果你想找到“2”所在的索引,你可以这样做,否则请详细说明:

storeString = [["","","",""],["","2","",""],["","","",""],["2","","",""]]

for i in storeString:
   if "2" in i:
     print(i.index("2"))

如果要获取该字符串中的列表,只需使用json加载其内容:

import json


list_ = json.loads('[["","","",""],["","2","",""],["","","",""],["2","","",""]]')

然后你可以迭代 list_ 随你的便